If a
set obtained by
interchanging the co-ordinates
of
each ordered
pair of
a function is a
function , then the given
function is an
invertible function and
the new function
is the inverse
function .
A function
has inverse if and only if it is a one-to-one
function .
E.g.
*
{(1,2),(3,4),(5,1)}
→ {(2,1),(4,3),(1,5)}
It is a
invertible function and its
inverse function
{(2,1),(4,3),(1,5)}.
{(1,2),(3,2),(5,1)}
→ {(2,1),(2,3),(1,5)}
It is a
function but not invertible
function . So Its can not
do inverse .
Definition: Lets f be
a One-to-One function with
domain X and range Y .The
inverse of f
is the function
g with domain
Y and Range X for which
f(g(x)) = x for every x in Y
and g(f(x)) = x for every x in X
So f is not One-to-One ,then it has no inverse function.
Procedure of
finding f-1(x)
1) Check whether the
function is One-to-One
2) Write the function y=f(x)
3) Solve for x (in terms of y)
4) Interchange x and y
5) Write y= f-1(x)
Properties :
i)
Domain
of f = Range of f-1
ii)
Range
of f = Domain of f-1
iii)
f-1
is One-to-One.
iv)
Inverse
of f-1 is f
Example :
Example :
y = f(x) =(x+1) / (2x-5)
Domain of f = R – {5/2
Here, y = (x+1)/(2x-5)
=> 2xy-5y=x+1
=> 2xy-x=5y+1
=> x(2y-1)=5y+1
So x = (5y+1) / (2y-1)
Interchanging x and y , we get ,
y = (5x+1) / (2x-1) = f-1(x)
Domain of f = R – {1/2
Range of f = R – {5/2}
Graphs of f and f-1
Graphs of f and f-1
The
graph of f and f-1 are reflections of
each other in the line y
= x . Tn the other words , the graphs of f
and f-1 are
symmetric with respect
to the line
y=x .
Such as , y =
x3
perfect
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